Control Engineering Basics
When a step of size 2 was applied to a first-order system, the output finally settled at 6 and reached about 63% of its final value 0.4 s after the input. Which of the following is the transfer function of this system?
- A3/(1 + 0.4s)
- B3/(1 + 2.5s)
- C6/(1 + 0.4s)
Show answer and explanation
Answer: A. 3/(1 + 0.4s)
The steady-state gain is the final output divided by the input size: 6 ÷ 2 = 3. The time a first-order step response takes to reach about 63% (1 − e^(−1)) of its final value is the time constant, so T = 0.4 s. The transfer function is therefore G(s) = 3/(1 + 0.4s). In this way, a first-order model can be built easily from the final value and the rise time of a step response.
- A. Correct. A steady-state gain of 3 and a time constant of 0.4 s.
- B. This puts 2.5, the reciprocal of the time constant, as the coefficient of s. The coefficient of s is the time constant itself.
- C. This uses the final output 6 directly as the gain. It must be divided by the input size 2.