Control Engineering Basics

A step of size 1 is applied at time 0 to a first-order system with the transfer function G(s) = 2/(1 + 0.5s). Which of the following is closest to the output at t = 1 s?

  1. AAbout 1.26
  2. BAbout 1.73
  3. C2
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Answer: B. About 1.73

The step response of a first-order system K/(1 + Ts) is y(t) = K(1 − e^(−t/T)), here with K = 2 and T = 0.5 s. Since t = 1 s is twice the time constant, y = 2 × (1 − e^(−2)) ≈ 2 × 0.865 ≈ 1.73. The response reaches about 63.2% of its final value at the time constant T, about 95% at 3T and about 99.3% at 5T.

  • A. This takes t/T as 1, the value at t = 0.5 s. At t = 1 s, twice the time constant has passed.
  • B. Correct. This is about 86.5% of the final value 2.
  • C. This is the final value. The output of a first-order system only approaches it with time and does not reach it in finite time.
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More Control Engineering Basics questions

  1. When a step of size 2 was applied to a first-order system, the output finally settled at 6 and reached about 63% of its final value 0.4 s after the input. Which of the following is the transfer function of this system?
  2. Which of the following is the range of the damping ratio ζ for which the step response of the second-order system G(s) = ωn²/(s² + 2ζωn s + ωn²) overshoots the final value and approaches it while oscillating?
  3. Which of the following is the correct pair of natural angular frequency ωn and damping ratio ζ for the second-order system with the transfer function G(s) = 25/(s² + 4s + 25)?
  4. A step is applied to a second-order system (standard form without zeros) with a damping ratio ζ = 0.5. Which of the following is closest to the overshoot (the maximum excursion beyond the final value, as a fraction of the final value)?
  5. Which of the following is the settling time, until the step response of the system G(s) = 25/(s² + 4s + 25) stays within ±2% of its final value, estimated with the approximation ts ≈ 4/(ζωn)?

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