Probability, Statistics and Queueing
Among 10 lottery tickets, 3 are winners. Two tickets are drawn one after the other, and a drawn ticket is not put back. Which of the following is the probability that both are winners?
- A1/45
- B1/15
- C9/100
Show answer and explanation
Answer: B. 1/15
The probability that the first ticket wins is 3/10. Given that the first ticket won, 2 of the remaining 9 tickets are winners, so the conditional probability that the second ticket wins is 2/9. The probability that both win is therefore 3/10 × 2/9 = 6/90 = 1/15. Thinking in combinations, dividing the 3C2 = 3 ways of choosing 2 of the 3 winners by the 10C2 = 45 ways of choosing 2 of the 10 tickets also gives 3/45 = 1/15.
- A. This counts only one pair of winners among the 45 ways of choosing 2 of the 10 tickets. There are 3 ways to choose 2 of the 3 winners.
- B. Correct. 3/10 × 2/9 = 1/15.
- C. This is (3/10)² = 9/100, the result when the drawn ticket is put back. Without putting it back, the probability that the second ticket wins changes to 2/9.
Continue: 9 more Probability, Statistics and Queueing questions