Control Engineering Basics
Which of the following correctly describes the Bode plot of an integrator G(s) = 1/s?
- AThe gain is 0 dB at every frequency, and the phase is −90° at every frequency
- BThe gain is a +20 dB/dec line passing through 0 dB at ω = 1 rad/s, and the phase is +90° at every frequency
- CThe gain is a −20 dB/dec line passing through 0 dB at ω = 1 rad/s, and the phase is −90° at every frequency
Show answer and explanation
Answer: C. The gain is a −20 dB/dec line passing through 0 dB at ω = 1 rad/s, and the phase is −90° at every frequency
The magnitude of G(jω) = 1/(jω) is 1/ω, so it is 0 dB at ω = 1 rad/s and falls by 20 dB for every tenfold increase in frequency. Since 1/j = −j, the phase is −90° at every frequency. Because the gain grows without limit at low frequencies, a system containing an integrator can bring the steady-state error to a step setpoint to zero. A +20 dB/dec line with a phase of +90° belongs to a differentiator s.
- A. The gain is not constant; it changes in inverse proportion to frequency.
- B. This is the Bode plot of a differentiator G(s) = s.
- C. Correct. An integrator has a gain slope of −20 dB/dec and a constant phase lag of 90°.