What is Ring resonator?

A looped waveguide that resonates only at wavelengths for which one round trip's optical length is an integer number of wavelengths. It is used as a wavelength filter or compact modulator. In silicon the resonance shifts by about 0.08 nm per °C, so heaters are often used to control its temperature.

Japanese name: リング共振器

Ring resonator appears in 3 practice questions across 1 topic, including Silicon photonics.

Ring resonator and transmission spectrum Ring resonator Circumference L Input Through Bus waveguide Resonates when the round-trip optical length = integer × λ Transm. Wavelength FSR Transmission dips at resonance Shorter ring → wider FSR FSR ≈ λ² ÷ (ng × L)
Ring resonator and transmission spectrum · View in diagrams

Field: Silicon photonics

Try it: questions about Ring resonator

Which correctly explains why a silicon ring resonator responds strongly only to specific wavelengths?

  1. AThe ring material is chosen to have a band gap that absorbs only that wavelength
  2. BLight can enter the ring only at the wavelength where the ring radius exactly equals the wavelength
  3. CAt wavelengths where the optical path length of one round trip is an integer multiple of the wavelength, the circulating light interferes constructively
Show answer and explanation

Answer: C. At wavelengths where the optical path length of one round trip is an integer multiple of the wavelength, the circulating light interferes constructively

In a ring resonator, part of the light in an adjacent bus waveguide transfers into the ring and circulates many times. At wavelengths where the optical length of one round trip (effective index × circumference) is an integer multiple of the wavelength, the phase lines up on every pass and the light builds up (resonance), causing a sharp dip in the light passing through the bus waveguide at that wavelength only. This property is used for filters that extract specific wavelengths and for compact modulators that shift the resonant wavelength electrically. There are multiple discrete resonant wavelengths, and rings with radii from a few µm to several tens of µm are used.

Which correctly describes what happens when the circumference of a ring resonator is shortened?

  1. AThe spacing between adjacent resonant wavelengths (FSR) becomes wider
  2. BThe spacing between adjacent resonant wavelengths (FSR) becomes narrower
  3. CResonance no longer occurs and all wavelengths pass through
Show answer and explanation

Answer: A. The spacing between adjacent resonant wavelengths (FSR) becomes wider

The FSR (free spectral range) is the spacing between adjacent resonant wavelengths, approximately FSR ≈ λ² / (ng × L) (ng is the group index, L the circumference), so it is inversely proportional to the circumference. For example, with λ = 1.55 µm, ng ≈ 4.2 and L ≈ 63 µm (radius about 10 µm), the FSR is about 9 nm. Halving the circumference roughly doubles the FSR, making it easier in WDM, which handles many wavelengths, to keep one ring from also responding to another wavelength. However, sharper bends increase bending loss, so there is a limit to how small the ring can be.

Ring resonator in the explanations

Questions that mention Ring resonator (3)

  1. Which correctly explains why a silicon ring resonator responds strongly only to specific wavelengths?
  2. Which correctly describes what happens when the circumference of a ring resonator is shortened?
  3. Why do optical circuits using ring resonators often place a heater near the ring to control its temperature?

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Related terms

Waveguide WDM (wavelength division multiplexing) Refractive index C-band Chromatic dispersion CPO (co-packaged optics) Edge coupler Extinction ratio Grating coupler Mach-Zehnder modulator

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