Digital Signal Processing Basics

A signal sampled at 48 kHz is analyzed with a 1024-point discrete Fourier transform (DFT). Which of the following is the spacing of the frequency bins?

  1. AAbout 23.4 Hz
  2. BAbout 46.9 Hz
  3. CAbout 93.8 Hz
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Answer: B. About 46.9 Hz

The bin spacing of an N-point DFT is Δf = fs/N, and 48000 ÷ 1024 = 46.875 Hz ≈ 46.9 Hz. Bin k corresponds to the frequency k × Δf: k = 0 is DC and k = N/2 = 512 is the Nyquist frequency of 24 kHz. Δf is also the reciprocal of the observation time T = N/fs ≈ 21.3 ms, so finer bins require a longer observation time.

  • A. This is fs/(2N) = 24000 ÷ 1024. The bin spacing is fs/N.
  • B. Correct. 48000 ÷ 1024 = 46.875 Hz.
  • C. This divides fs by the number of positive-frequency bins, N/2 = 512 (48000 ÷ 512).
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More Digital Signal Processing Basics questions

  1. Let k = 0 be the DC bin. When a 1 kHz sine wave sampled at 8 kHz is analyzed with a 256-point DFT, which of the following is the index k of the bin where the peak appears on the positive-frequency side?
  2. A 64-point DFT of a real signal x[n] gives X[10] = 3 + 4j. Which of the following is X[54]?
  3. The DFT of the 8-point real signal x[n] = {3, 1, 3, 1, 3, 1, 3, 1} is defined as X[k] = Σx[n]e^(−j2πkn/8). Which of the following is the value of X[4], the bin at the Nyquist frequency?
  4. Suppose an N-point DFT takes about N² operations when computed from its definition and about N log₂N operations with the FFT (fast Fourier transform). For N = 1024, which of the following is closest to the reduction in the number of operations achieved by the FFT?
  5. A 256-point signal is followed by 768 zeros (zero padding) and a 1024-point DFT is computed. Compared with computing the DFT of the 256 points as they are, which of the following is correct?