Digital Signal Processing Basics
A signal sampled at 48 kHz is analyzed with a 1024-point discrete Fourier transform (DFT). Which of the following is the spacing of the frequency bins?
- AAbout 23.4 Hz
- BAbout 46.9 Hz
- CAbout 93.8 Hz
Show answer and explanation
Answer: B. About 46.9 Hz
The bin spacing of an N-point DFT is Δf = fs/N, and 48000 ÷ 1024 = 46.875 Hz ≈ 46.9 Hz. Bin k corresponds to the frequency k × Δf: k = 0 is DC and k = N/2 = 512 is the Nyquist frequency of 24 kHz. Δf is also the reciprocal of the observation time T = N/fs ≈ 21.3 ms, so finer bins require a longer observation time.
- A. This is fs/(2N) = 24000 ÷ 1024. The bin spacing is fs/N.
- B. Correct. 48000 ÷ 1024 = 46.875 Hz.
- C. This divides fs by the number of positive-frequency bins, N/2 = 512 (48000 ÷ 512).