What is Allowable power dissipation?

The maximum power a package may dissipate, written Pd. It is set by the maximum junction temperature and the thermal resistance, and above a certain ambient temperature (often 25 °C) it must be reduced in proportion to temperature.

Japanese name: 許容損失

Allowable power dissipation appears in 2 practice questions across 1 topic, including How to read datasheets.

Series thermal-resistance model With a heat sink Tj Tc Ts Ta θJC θCS θSA Junction Case Heat sink Ambient Heat flow P (power) acts as the current Tj = Ta + P × (θJC + θCS + θSA) Estimating with θJA only Tj Ta θJA Tj = Ta + P × θJA θJA is measured on a test board and varies with mounting
Series thermal-resistance model · View in diagrams

Field: How to read datasheets

Try it: questions about Allowable power dissipation

An IC with maximum junction temperature Tj(max) = 125 °C and θJA = 50 °C/W is used at an ambient temperature Ta = 85 °C. What is the upper limit on allowable power dissipation?

  1. A0.8 W
  2. B2.5 W
  3. C1.7 W
Show answer and explanation

Answer: A. 0.8 W

Junction temperature is given by Tj = Ta + P × θJA. Solving for P gives P = (Tj(max) − Ta)/θJA = (125 − 85)/50 = 0.8 W. The higher the ambient temperature, the smaller the allowable temperature rise, and so the smaller the allowable power. 2.5 W is the mistake of forgetting to subtract the ambient temperature (125/50), and 1.7 W is the mistake of computing 85/50. In practice, considering that θJA varies with the board and allowing derating margin, design to keep power below the calculated value.

A package's allowable power dissipation is 1.0 W up to an ambient temperature of 25 °C, and above that it decreases linearly to 0 W at 150 °C. What is the allowable power dissipation at an ambient temperature of 75 °C?

  1. A0.6 W
  2. B0.4 W
  3. C0.5 W
Show answer and explanation

Answer: A. 0.6 W

It decreases by 1.0 W over the 125 °C span from 25 °C to 150 °C, so the slope is 1.0 W ÷ 125 °C = 8 mW/°C. 75 °C is 50 °C above 25 °C, so the reduction is 50 × 8 mW = 0.4 W, and the allowable dissipation is 1.0 − 0.4 = 0.6 W. 0.4 W is the reduction itself, and 0.5 W is the mistake of a proportional calculation starting from 0 °C. This curve is determined by the maximum junction temperature of 150 °C and θJA (here 125 °C/W); note also that, like θJA, it is a value for a test board.

Questions that mention Allowable power dissipation (2)

  1. An IC with maximum junction temperature Tj(max) = 125 °C and θJA = 50 °C/W is used at an ambient temperature Ta = 85 °C. What is the upper limit on allowable power dissipation?
  2. A package's allowable power dissipation is 1.0 W up to an ambient temperature of 25 °C, and above that it decreases linearly to 0 W at 150 °C. What is the allowable power dissipation at an ambient temperature of 75 °C?

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