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Silicon photonics

In photonics-electronics convergence, what is the main aim of placing optical transceivers right next to electronic circuits?

  1. ATo eliminate long electrical wiring, reducing loss and power, and shorten the distance at which optical transmission becomes advantageous
  2. BTo make optical components easy to unplug and replace from the front panel
  3. CTo eliminate electrical-optical conversion and perform all computation with light alone
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Answer: A. To eliminate long electrical wiring, reducing loss and power, and shorten the distance at which optical transmission becomes advantageous

Electrical wiring loses more as signals get faster and distances longer, and the circuits that compensate consume power. Optical loss is nearly independent of distance at data-center scales, but electrical-optical conversion costs power. Photonics-electronics convergence places optical components right next to electronic circuits to eliminate long electrical wiring and reduce conversion power, shortening the distance at which optics becomes the better choice. CPO is a representative form, and later steps aim to make links between and within chips optical.

  • A. Correct. The aim is to shorten electrical wiring and cut power.
  • B. The closer the integration, the harder unplugging and replacement become.
  • C. Computation stays electronic; mainly signal transmission becomes optical.
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  1. Even as photonics-electronics convergence advances, why is electrical wiring expected to remain in use for very short links such as those inside a chip?
  2. In long-haul optical fiber communication, what is the main reason wavelengths around 1.55 µm (C-band) are widely used?
  3. For relatively short-reach optical links inside data centers, which is a correct reason wavelengths around 1.31 µm (O-band) are often used?
  4. Which correctly pairs the photon energy of 1.55 µm light with its behavior in a silicon waveguide? (E [eV] ≈ 1.24 / λ [µm])
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