Silicon photonics

What is the main reason rib waveguides—shallowly etched so that thin silicon slabs remain on both sides—are often used in silicon optical modulators?

  1. AThey confine light more tightly than fully etched strip waveguides and can be bent sharply at small radii
  2. BThe slabs allow electrical connection from electrodes placed at a distance to the pn junction in the waveguide
  3. CLight is amplified in the slabs, offsetting the loss generated in the modulator
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Answer: B. The slabs allow electrical connection from electrodes placed at a distance to the pn junction in the waveguide

In a rib waveguide, the slabs left on both sides are doped to connect the electrodes to the pn junction at the center of the waveguide. Placing metal electrodes right next to the waveguide would absorb light, so being able to place them away from where the light travels is important. In contrast, fully etched strip waveguides have a large lateral index contrast and confine light tightly, making them suited to sharp bends and miniaturization. Rib waveguides confine light weakly, and sharp bends cause light to leak into the slabs. Silicon slabs do not amplify light.

Silicon waveguide cross-sections (strip and rib) SiO₂ (n ≈ 1.45) Si (n ≈ 3.5) Optical mode SiO₂ cladding Buried oxide (BOX) Si substrate Width ~500 nm t = 220 nm SiO₂ cladding Buried oxide (BOX) Si substrate Width ~500 nm Slab Strip waveguide Rib waveguide Strong confinement, tight bends Slab connects to electrodes
Silicon waveguide cross-sections (strip and rib) · View in diagrams
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More Silicon photonics questions

  1. Which is a correct advantage of a grating coupler for connecting optical fiber to a silicon photonic circuit?
  2. Which correctly describes an edge coupler, which couples to optical fiber at the chip facet, compared with a grating coupler?
  3. Why is an inverse taper, in which the silicon waveguide narrows toward the chip edge, used in edge couplers?
  4. When a silicon photonic circuit receives light from standard single-mode fiber, which is a correct reason polarization becomes an issue?
  5. Which correctly describes how a Mach-Zehnder modulator converts a change in optical phase into a change in optical intensity?