Silicon photonics

Which correctly describes how a Mach-Zehnder modulator converts a change in optical phase into a change in optical intensity?

  1. AIt splits light into two arms, creates a phase difference between the arms, then recombines them so they interfere
  2. BIt circulates light many times in a ring-shaped resonator so that only specific wavelengths are absorbed
  3. CShining phase-shifted light directly onto a photodetector turns the phase difference into a difference in current
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Answer: A. It splits light into two arms, creates a phase difference between the arms, then recombines them so they interfere

In a Mach-Zehnder modulator, incoming light is split equally into two arms, the arms' refractive indices are changed by an electrical signal to create a phase difference, and the light is recombined into one path. If the phase difference between the two beams is 0 they interfere constructively (bright); if it is π (half a wavelength) they cancel (dark); in between, the intensity depends on the phase difference. This places the signal on intensity changes that a photodetector can detect. A photodetector only outputs current according to light intensity and cannot directly detect phase differences. Using a resonator is the approach of the ring modulator.

Mach-Zehnder modulator Input light Output light Electrode (phase shifter) Voltage changes the arm's index, creating a phase difference Split in two Recombine & interfere Phase diff. 0 Constructive: bright Phase diff. π Destructive: dark
Mach-Zehnder modulator · View in diagrams
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More Silicon photonics questions

  1. Why is the carrier dispersion effect (plasma dispersion effect) used to change the refractive index with an electrical signal in silicon optical modulators?
  2. Why do high-speed silicon modulators often use the depletion type, which applies reverse bias to the pn junction of the phase shifter to vary the depletion width?
  3. Which correctly describes VπL ("V-pi-L"), a figure of merit for Mach-Zehnder modulators?
  4. Which correctly explains why a silicon ring resonator responds strongly only to specific wavelengths?
  5. Why do optical circuits using ring resonators often place a heater near the ring to control its temperature?