Silicon photonics

In CWDM (coarse wavelength division multiplexing) for data center optical transceivers, wavelengths are spaced 20 nm apart, for example 1271, 1291, 1311 and 1331 nm. What is the main reason for the wide spacing?

  1. AWider wavelength spacing reduces fiber loss and dispersion, so light reaches farther without amplifiers
  2. BEven without control to keep the laser temperature constant, temperature-induced wavelength drift is unlikely to overlap the adjacent wavelength
  3. CMultiplexers and demultiplexers with spacing narrower than 20 nm are fundamentally impossible to build
Show answer and explanation

Answer: B. Even without control to keep the laser temperature constant, temperature-induced wavelength drift is unlikely to overlap the adjacent wavelength

The lasing wavelength of a semiconductor laser changes with temperature; a DFB laser shifts by about 0.1 nm per 1 °C. A temperature change of several tens of °C shifts it by several nm, so with narrow spacing it would overlap the adjacent wavelength. CWDM's wide 20 nm spacing allows lasers to be used without temperature control by Peltier elements or similar, lowering cost and power consumption. In contrast, DWDM, used for long-haul communication, packs many wavelengths at narrow spacings such as 0.8 nm (100 GHz), so temperature control is essential. Widening the spacing does not reduce fiber loss.

Practice this topic Back to topic

Books on Silicon photonics Ad

As an Amazon Associate I earn from qualifying purchases.

More Silicon photonics questions

  1. For WDM in the C-band (around 1.55 µm), a frequency spacing of 100 GHz corresponds to roughly what wavelength spacing? (Δλ ≈ λ² × Δf / c, c = 3×10⁸ m/s)
  2. For optical transceivers, which correctly compares the parallel scheme, which sends one wavelength on each of four fibers, with the CWDM scheme, which combines four wavelengths onto one fiber?
  3. Which correctly describes the extinction ratio, a measure of optical transmit signal quality?
  4. For high-speed links of a few m or more, such as those spanning racks, what is the main reason optical fiber has an advantage over copper cables and board traces?
  5. Which is a correct advantage of pluggable optical transceivers inserted into a switch's front panel?