Circuit and electromagnetism basics
In a voltage divider made of two 10 kΩ resistors in series across a 10 V DC supply, a 10 kΩ load resistor is connected in parallel with the lower (ground-side) resistor. Which is closest to the output voltage (across the lower resistor)?
- A5 V
- BAbout 3.3 V
- CAbout 6.7 V
Show answer and explanation
Answer: B. About 3.3 V
With the load connected, the lower resistor and the load are in parallel, giving 10 × 10/(10 + 10) = 5 kΩ. The output is 10 V × 5/(10 + 5) ≈ 3.33 V, a large drop from the 5 V with no load. Treating the output as a Thevenin equivalent (5 V, 5 kΩ) driving 10 kΩ gives the same result: 5 V × 10/(5 + 10) ≈ 3.33 V. To reduce loading, make the divider resistors much smaller than the load or buffer the output (voltage follower).
- A. 5 V is the voltage with no load connected.
- B. Correct. 10 V × 5 kΩ/(10 kΩ + 5 kΩ) ≈ 3.33 V.
- C. About 6.7 V is the result if the load were placed across the upper resistor.
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