System Architecture and Reliability
RAID 6 is built from six disks with a capacity of 8 TB each. Which is the correct combination of the capacity available for storing data and the number of disks that can fail at the same time without losing data?
- A32 TB, up to 2 disks
- B40 TB, up to 1 disk
- C48 TB, up to 2 disks
Show answer and explanation
Answer: A. 32 TB, up to 2 disks
RAID 6 writes two kinds of parity distributed across the disks and uses two disks' worth of capacity for parity. The capacity available for data is (6 − 2) × 8 TB = 32 TB, and no data is lost even if up to two disks fail at the same time. As disk capacities grow, recovering (rebuilding) from one disk failure takes longer and the risk of another disk failing in the meantime increases, so RAID 6 is often chosen over RAID 5.
- A. Correct. (6 − 2) × 8 TB = 32 TB, and it tolerates two disk failures.
- B. This is the value for RAID 5. Parity takes one disk, so it tolerates only one disk failure.
- C. This is the capacity of all six disks and does not subtract the parity.
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