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For an op-amp with a slew rate of 0.5 V/µs, roughly what is the maximum frequency at which a sine wave with an amplitude (peak) of 10 V can be output without distortion?
- AAbout 8 kHz
- BAbout 50 kHz
- CAbout 800 Hz
Show answer and explanation
Answer: A. About 8 kHz
The maximum slope of a sine wave Vp sin(2πft) is 2πf × Vp. If this exceeds the slew rate, the output cannot keep up and distorts into a triangle-like wave. f = SR/(2π × Vp) = 0.5 × 10⁶ V/s ÷ (2π × 10 V) ≈ 8 kHz. This is called the full-power bandwidth, and it falls as amplitude increases. Note that even if the gain-bandwidth product (GBW) is sufficient, bandwidth for large-amplitude signals is limited by the slew rate. About 50 kHz is the value obtained by forgetting to multiply by 2π.