Circuit Analysis: AC, Linear Circuits and Transients
The circuit in the figure contains a current-controlled voltage source that produces a voltage r·i (r = 3 Ω) proportional to the current i in R1. With E = 10 V and R1 = 2 Ω, which of the following is the Thevenin equivalent resistance Rth seen from terminals a-b?
- A−1 Ω
- B2 Ω
- C5 Ω
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Answer: C. 5 Ω
The voltage at terminal a is E minus the voltages across R1 and the dependent source: Va = 10 − 2i − 3i = 10 − 5i. With the terminals open, i = 0, so the open-circuit voltage is 10 V; with them shorted, 10 − 5i = 0 gives a current of 2 A, so Rth = 10/2 = 5 Ω. Setting E to 0 and applying a voltage V to the terminals gives V = −5i, so V/(−i) = 5 Ω as well. A dependent source takes its value from a current in the circuit, so it must not be set to 0 the way an independent source is.
- A. This is 2 − 3 = −1 Ω, taking the dependent source in the opposite direction (aiding E). In the figure, i enters the + side, so the source acts as a voltage drop.
- B. This sets the dependent source to 0 (shorted) like an independent source and sees only R1.
- C. Correct. Voc/Isc = 10 V/2 A = 5 Ω.
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